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0 is instable

If $ \sigma$ is positive, the amplitude of the perturbation will increase. We are in this case when $ \nu -k^2 \lambda > 0 $. As in the previous part it gives the condition of instability for the order n : $ \nu >(2 \pi n)^2$

The results which illustrate this theoretical behaviour are is the part 3.2.1



Julien Delbove
2000-11-23