EXAMPLE , PART II



 
Example I :

The following results come from computation with a two components flow (air-water) in a  89.9 meters lenght horizontal pipe .
                                        Pipe diameter is constant equal to 5.3 cm .
                                        Components velocities : U(gas) = 3.75 m/s
                                                                                    U(liquid) = 1.0 m/s
                                        The flow temperature is constant in the pipe, equal to 20 degrees C (293 K) .

Input files are :
 
test

TITLE=test
NOTE=conduite horizontale
NOTE=ecoulement eau/air
NOTE= 111
TOP=test.TOP
GEO=test.GEO
THE=test.THE
MSH=test.MSH
PVT=test.PVT
SCE=test.SCE
STO=test.STO
 

TACITE..JOB

test
06/10/00 11h30am
TITLE=test 
NOTE=conduite horizontale
NOTE=ecoulement eau/air
NOTE= 111 
TOP=test.TOP
GEO=test.GEO
THE=test.THE
MSH=test.MSH
PVT=test.PVT
SCE=test.SCE
STO=test.STO
 

 

test.TOP

0.d0        0.d0 
89.9d0      0.d0
 

test.GEO

PIPE 
0.d0         0.053d0     0.d0
89.9d0       0.053d0     0.d0
EQUIPMENT
so           1           0.d0
si           2           89.9d0

 

test.SCE

STABILIZE = -1
STOP_TIME = 100

EQUIPMENT = so
UPST_COMP1
T=0   BC=0.0098d0
UPST_COMP2
T=0   BC=2.2d0

EQUIPMENT = si
DOWN_PRES
T=0   BC=1.d5
 

test.MSH

GRID 
X=0.d0    NB=10

 

test.PVT

5                              ! Type: 1=correlations 
1.d5        293.d0      ! normal pressure and temperature 
1.20d0                     ! TPN gas density 
1.5d-5                     ! TPN gas viscosity 
1000.d0                   ! TPN liquid density 
1.5d-6                    ! TPN liquid viscosity 
74.d-3                    ! TPN interfacial stress 
1000.d0                  ! Specific Heat of Gas 
1.86d0                    ! Specific Heat of Liquid 
2.54d-2                 ! Gas conductivity 
0.59d0                   ! Liquid conductivity 
0.d0                       ! k1 
0.d0                       ! k2
 

test.THE


0.d0    293.d0
89.9d0  293.d0 
 

test.STO

PERIOD=10.d0
STYLE=ASCII
 

Temperature and Pressure profiles are :





 
 
Example II :

The following results come from computation with a two components flow (Gasoil-methan/ethan) in a pipe as the picture below :





Input files are :
 
 
 
 
 
case

 TITLE=case 
 NOTE=  conduite sous-marine et souterraine 
 NOTE=  liquide gazole 
 NOTE=  gaz methane/ethane 
 TOP=case.TOP 
 GEO=case.GEO 
 THE=case.THE 
 MSH=case.MSH 
 PVT=case.PVT 
 SCE=case.SCE 
 STO=case.STO 
 

TACITE.JOB

  case 
  27/10/00 11h00am 
 TITLE=case 
 NOTE=conduite sous-marine et souterraine 
 NOTE=liquide gazole 
 NOTE= gaz methane/ethane 
 TOP=case.TOP 
 GEO=case.GEO 
 THE=case.THE 
 MSH=case.MSH 
 PVT=case.PVT 
 SCE=case.SCE 
 STO=case.STO 

case.TOP 

  0.d0        0.d0 
  800.d0      800.d0 
  50800.d0    800.d0 
  52300.d0    2300.d0

case.GEO

 PIPE 
 0.d0         0.1397d0     0.d0
 800.d0       0.1397d0     0.d0
 50800.d0     0.1397d0     0.d0
 52300.d0     0.1397d0     0.d0

 EQUIPMENT
 so           1           0.d0
 si           2           52300.d0
 p            6           800.d0

 PUMP
 130.d0   0.d0    150.d0
 250.d5
 16 1
 1
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0
 0.135d0  0.20d0   0.20d0   0.5d0

case.SCE

STABILIZE = 0
 STOP_TIME = 300

EQUIPMENT = so
 UPST_COMP1
 T=0   BC=0.276d0
  UPST_COMP2
 T=0   BC=24.34d0

EQUIPMENT = si
 DOWN_PRES
T=0   BC=10.d5

EQUIPMENT = p
 PUMP_VELO
  T=0        BC=130.d0

 

case.MSH

 GRID 
 X=0.d0      NB=8
 X=800.d0    NB=300 
 X=50800.d0  NB=15 

case.PVT

 5                                ! Type: 1=correlations 
 42.d5        297.d0     ! normal pressure and temperature 
 30.d0                        ! TPN gas density 
 4.d-7                       ! TPN gas viscosity 
 882.                          ! TPN liquid density 
 9.15d-6                   ! TPN liquid viscosity 
 0.023d0                    ! TPN interfacial stress 
 2430.d0                   ! Specific Heat of Gas 
 1880.d0                   ! Specific Heat of Liquid 
 2.54d-2                  ! Gas conductivity 
 0.59d0                     ! Liquid conductivity 
 0.d0                         ! k1 
 0.d0                         ! k2
 

case.THE


 0.d0       333.d0
 800.d0     277.5d0 
 50800.d0   277.5d0 
 51300.d0   277.5d0
51800.d0   281.d0
 52300.d0   295.d0
 

case.STO

 PERIOD=30.d0
  STYLE=ASCII


 

Flow Pattern and slug fraction profiles are :